8(97)6 ; 4(56)5 ; 6(75)4 ; 7(?)8

a. 98

b. 97

c. 89

d. 88

**Answer:** c. 89

**Explanation:**

In 8(97)6 we can have 97- 86 = 11

4(56)5 we can have 56 - 45 = 11

6(75)4 we can have 75 - 64 = 11

So, the difference is 11.

? - 78 = 11

So, ? = 78+11 = 89

cdd ____cd _____c _____ ddc

a. d d c

b. d c d

c. d c c

d. c d c

**Answer:** d. c d c

**Explanation:**

From first term, we see that c comes before 'dd'. So, last blank has to be c.

From last term, we see that after dd, c comes. So, first blank is c.

From first term, we can infer that after cd, d comes so that we get cdd.

So, second blank has to be d.

Answer is c d c

Which of the following will fit the above sequence?

a. OIF

b. MHD

c. MHF

d. NJC

**Answer:** a. OIF

**Explanation:**

**Alphabets and their positions**

A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z |

1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 |

Position of Z is 26

Position of Y is 25

26-25 = 1 = Position of A

U=21; S=19; 21-19=2=B

P=16; K=11; 16-11=5=E

Only option 1 satisfies this condition

O=15; I=9; 15-9 = 6 = F

3, 15, 35, ? , 99, 143

a. 81

b. 77

c. 63

d. 69

**Answer:** c. 63

**Explanation:**

Here if we look closely we can see that 3 is near to 4 which is 2^{2}

That is 3 = 4 -1 = 2^{2} - 1

Also 15 is near to 16 which is 4^{2}

That is 15 = 16-1 = 4^{2} - 1

And 35 = 36-1 = 6^{2} - 1

99 = 100 - 1 = 10^{2} - 1

143 = 144-1 = 12^{2} - 1

So it is squares of even numbers i.e. 2, 4, 6, etc. so next should be 8 and then 10, 12.

So missing term is 82 - 1 = 64 - 1 = 63