Solution:
Armstrong Number:
An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 153 is an Armstrong number since 1*1*1 + 5*5*5 + 3*3*3 = 153
We will use a "for loop" to find the Armstrong numbers from the array.
Program
#include<conio.h>
#include<stdio.h>
#define max 100
void armstrng(int[],int);
void main()
{
int a[max], n, i=0;
printf("Enter the limit of array: ");
scanf("%d", &n);
printf("Enter the elements of array: ");
for(i=0; i<n; i++)
{
scanf("%d",&a[i]);
}
armstrng(a,n);
getch();
}
void armstrng(int a[max],int n)
{
int i=0, temp, sum=0, rem, c=0;
for(i=0; i<n; i++)
{
sum=0;
temp=a[i];
while(a[i]!=0)
{
rem=a[i]%10;
sum=sum+rem*rem*rem;
a[i]=a[i]/10;
}
if(temp==sum)
{
c++;
}
}
printf("\nTotal armstrng no is: %d ",c);
}
Output:
