Write a C program to generate following pattern for 'n' lines:

Solution:
Output:


Solution:
#include<stdio.h>
int main()
{
int i,j,n, a=1;
printf("How Many Lines \nYou Want to Print: ");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
printf("%d ",a);
a=a+2;
}
printf("\n");
}
return 0;
}
Output:



