Answer: d. 72 days
Explanation:
| Let work done by Ram in 1 day = | 1 | & by Shyam in 1 day = | 1 |
| R | S |
| Both complete work in 24 days. So in 1 day, together they complete = | 1 | = | 1 | + | 1 |
| 24 | R | S |
For 20 days both work together, so work done by them = 20 ![]() | 1 | + | 1 | = | 5 |
| R | S | 6 |
Remaining work 1 - | 5 | = | 1 | is done by Ram alone in 6 days |
| 6 | 6 |
| Work done by Ram in 6 days = | 1 | = 6![]() | 1 | ![]() |
| 6 | R |
| ∴ | 1 | + | 1 | = | 1 |
| 36 | S | 24 |
Answer: a. 20 days
Explanation:
Tip:
Men = M; Days = D; Time/Hours = T; Work = W
M1D1T1W2 = M2D2T2W1
Note that - W2 is on left side and W1 is on right side
Remember - Convert either all adults to children or all children to adults.
| a. | 7 | times more efficient |
| 15 |
| b. | 7 | times more efficient |
| 12 |
| c. | 3 | times more efficient |
| 4 |
| d. | 4 | times more efficient |
| 3 |
| Answer: d. | 4 | times more efficient |
| 3 |
Tip:
Men = M; Days = D; Time/Hours = T; Work = W
M1D1T1W2 = M2D2T2W1
Note that - W2 is on left side and W1 is on right side
| ∴ E = | 4 | = these many times more efficient |
| 3 |
Answer: a. 45
Explanation:
Tip:
Men = M; Days = D; Time/Hours = T; Work = W
M1D1T1W2 = M2D2T2W1
Note that - W2 is on left side and W1 is on right side
| Remaining work = 1 - | 1 | = | 2 |
| 3 | 3 |
| Thus (75+E) employees complete | 2 | work in 50 hours. |
| 3 |
| ∴ 75 employees x 40 hours x | 2 | = (75 + E) x 50 hours x | 1 |
| 3 | 3 |
Answer: d. 48 days
Explanation:
Let each tree take T amount of water every day.
So 72 trees take 72T water in one day.
| With 10% reduction each tree will consume | 90T | amount each day |
| 100 |
| So 90 Trees take 90 | 90T | amount in one day |
| 100 |
| ∴ 72T x 54 = 90 x | 90T | x D |
| 100 |