Answer: b. Rs. 656.10, 11.11%
Explanation:
If Raj allows, one more year, time period becomes 4 years.
4 years - 3 years = 1 year
Thus, we can say that Rs. 900 becomes Rs. 1000 in 1 year.
∴ Interest = Rs. 1000 - Rs. 900 = Rs. 100
For 1 year time period, Simple Interest = Compound Interest
| ∴ | P x R x T | = | 900 x R x 1 | = Rs. 100 |
| 100 | 100 |
| ∴ R = | 100 | % = 11.11% |
| 9 |
| Also, in 3 years by compound interest the original sum becomes Rs. 900 at the rate 11.11% or | 100 | %. |
| 9 |
| ∴ Amount = Rs. 900 = P | ![]() | 1 + | R | ![]() | n |
| 100 |
| ∴ 900 = P | ![]() | 1 + | 100 | ![]() | 3 |
| 9 x 100 |
Answer: c. Rs. 464.10
Explanation:
| Simple Interest = | P x R x T | = Rs. 400 |
| 100 |
| ∴ | P x 10 x 4 | = 400 |
| 100 |
| For Compound Interest, Amount = P | ![]() | 1 + | R | ![]() | n |
| 100 |
| ∴ Amount = 1000 | ![]() | 1 + | 10 | ![]() | 4 |
| 100 |
Answer: c. 79,860
Explanation:
| Population after n years = P | ![]() | 1 ± | R | ![]() | n |
| 100 |
| Population after 3 years = 60,000 | ![]() | 1 + | 10 | ![]() | 3 |
| 100 |
| = | 60,000 x 11 x 11 x 11 | = 79,860 |
| 10 x 10 x 10 |
Answer: c. Rs. 14400
Explanation:
Tip:
In cases where rate of interest is given and the number of installments = 2, then you should use the following trick to solve such problems quickly.
(1st fraction x 2nd fraction) x Installment = Sum
| ∴ R = 20% = | 20 | = | 1 |
| 100 | 5 |
| Next, derive first fraction as = | Denominator | = | 5 | = | 5 |
| Numerator+Denominator | 1+5 | 6 |
| Using this fraction, derive 2nd fraction as = | Numerator+Denominator | = | 5+6 | = | 11 |
| Denominator | 6 | 6 |
| ∴ | ![]() | 5 | x | 11 | ![]() | x Installment = Sum |
| 6 | 6 |
| ∴ | ![]() | 5 | x | 11 | ![]() | x Installment = 22000 |
| 6 | 6 |
Answer: c. Rs. 11250