Q. Write a C++ program to check the given number is Armstrong number or not.
Answer:
If the sum of cubes of individual digit is equal to that number itself, it is called Armstrong number. For example:
153 = 1 * 1 * 1 + 5 * 5 * 5 + 3 * 3 * 3
= 1 + 125 + 27
= 153
153 is an Armstrong number, where 123 is not an Armstrong number.
123 = 1 * 1 * 1 + 2 * 2 * 2 + 3 * 3 * 3
= 1 + 8 + 27
= 36
Output:
Answer:
If the sum of cubes of individual digit is equal to that number itself, it is called Armstrong number. For example:
153 = 1 * 1 * 1 + 5 * 5 * 5 + 3 * 3 * 3
= 1 + 125 + 27
= 153
153 is an Armstrong number, where 123 is not an Armstrong number.
123 = 1 * 1 * 1 + 2 * 2 * 2 + 3 * 3 * 3
= 1 + 8 + 27
= 36
#include<iostream>
using namespace std;
int main()
{
int n, nu, num=0, rem;
cout<<"\n Enter any Positive Number : ";
cin>>n;
nu=n;
while(nu!=0)
{
rem=nu%10;
num=num + rem*rem*rem;
nu=nu/10;
}
if(num==n)
{
cout<<"\n Number is Armstrong";
}
else
{
cout<<"\n Number is Not Armstrong";
}
return 0;
}
Output:
