Answer: a. 2
The symbols move clockwise. Also, they duplicate at bottom or top positions.
In 2nd figure, they duplicate at bottom. So, when P comes at bottom, it becomes PP.
In 3rd figure, they should duplicate at top. So, when Arrow comes at top, it should become Arrow-Arrow.
In 4th figure, they duplicate at bottom. So, when C comes at bottom, it becomes CC.
In 5th figure, they duplicate at top. So, when S comes at bottom, it becomes SS.
Answer: b. 2
Here there are 8 diamonds.
In the 1st one there are 2 shaded sections. In the 2nd there are 3 shaded sections.
The shaded region moves in a clockwise fashion.
In 3rd there are 4 shaded sections. Then all go blank. Then the shaded region is moving in anti-clockwise manner from 5th-8th diamond.
9th diamond must be blank.
Also, if you observe first diamond it has 2 shaded sections. So, what will be before that? There will be just one shaded area in. And we have to move back i.e. anti-clockwise. That will be 10th diamond. So, answer is Option 2.
Answer: c. 3
1st figure has 0 scattered dark circles. 2nd figure has 1scattered dark circle.
3rd figure has 2 scattered dark circles and so on.
Also, the longer line in the figures, has its last dark circle always touching the boundary of the square.
Either the shorter or the longer line, whichever is straight horizontal or straight vertical, always are at a distance of two rows or columns from the boundary.
Only answer figure 3 satisfy these conditions.
Answer: d. 4
The middle figure inverts and one part becomes shaded.
So, in answer image no shaded part and inverted middle part must be there.
Reflection of Z as seen in water is taken and written on right side in 2nd figure.
Same way reflection of 6 as seen in water is taken and written on left side in 2nd figure.
Use the inverse of this to get the answer as option d i.e. answer figure 4.