Simple Interest Questions and Answers
Learn and practice the chapter "Simple Interest" with these solved Aptitude Questions and Answers. Each question in the topic is accompanied by a clear and easy explanation, diagrams, formulae, shortcuts and tricks that help in understanding the concept.Use of Simple Interest Questions
The questions and examples given in this section will be useful to all the freshers, college students and engineering students preparing for placement tests or any competitive exam like MBA, CAT, MAT, SNAP, MHCET, XAT, NMAT, GATE, Bank exams - IBPS, SBI, RBI, RRB, SSB, SSC, UPSC etc.Practice with this online test to crack your placements and entrance tests!
a. Rs. 8600
b. Rs. 9000
c. Rs. 9050
d. Rs. 9300
Answer: b. Rs. 9000
Explanation:
| Simple Interest = | PRT |
| 100 |
| Rate of interest = R = 8% quarterly = | R | = | 8 | = 2% |
| 4 | 4 |
Amount after 2.5 years = Principal + Simple Interest
| Amount = 7500 + | 7500 x 10 x 2 | = 7500 + 1500 = Rs. 9000 |
| 100 |
| For half yearly interest:- R = | R | and T= 2T |
| 2 |
| For quarterly interest:- R = | R | and T= 4T |
| 4 |
| For monthly interest:- R = | R | and T= 12T |
| 12 |
2. Sujoy went to a mobile shop to buy a new mobile phone. The shop is running an offer which says, you can buy the mobile phone at 20,000 Rs cash or you can initially make a payment of Rs 4000 and pay 4 equal monthly installments. The rate of interest charged will be 8% pa. Find the value of installment to be paid each month.
a. Rs. 4000
b. Rs. 4050.33
c. Rs. 4066.01
d. Rs. 4106.67
Answer: c. Rs. 4066.01
Explanation:
Down payment = Rs. 4000
Remaining Amount = Rs. 20000 - Rs. 4000 = Rs. 16000
After 4 months total amount to be paid = 16000 + Simple Interest on 16000
| Simple Interest = | PRT | ; T = 4 months = | 4 | years |
| 100 | 12 |
| ∴ Total Amount = 16000 + | 16000 x 8 x 4 | = 16000 + 426.67 = Rs. 16426.67 |
| 12 x 100 |
Now how to calculate installments?
Total installments = 4 (One installment per month)
Simple and Easy rule -
If there are 'n' installments, then, 1st installment will have interest for (n-1) months, 2nd will have interest for (n-2) months and so on.
So in this case, n=4
∴ 1st installment will have interest for 3 months (n-1 = 4-1=3 months)
2nd installment will have interest for 2 months (n-2 = 4-2=2 months)
3rd installment will have interest for 1 month (n-3 = 4-3=1 month)
4th installment will have no interest (n-4 = 4-4=0 months)
Let each installment be of Rs. A
Total Amount = 4 Installments + Interest on those 4 Installments
| ∴ Total Amount = 4A + | P x R x T |
| 100 |
P = A (same amount 'A' for all installments)
From above rule we can calculate effective time period 'T'
T (for interest calculation) = 3months + 2 months + 1 month + 0 months
| ∴ T = 6months = | 6 | years |
| 12 |
| ∴ Total Amount = 4A + | A x 8 x 6 | = 4A + | 4A | = | 101A |
| 100 x 12 | 100 | 25 |
| ∴ 16426.67= | 101A |
| 25 |
Since rate of interest is same we can use above short cut.
If rate of interest or installment amount (A) or both varies then we have to calculate interest
| separately for each installment by applying formula SI = | PRT | for every installment. |
| 100 |
3. In 30 years an amount becomes 5 times the original amount. What is the rate of interest?
a. 6.67%
b. 12.5%
c. 13.33%
d. 24%
Answer: c. 13.33%
Explanation:
Original amount = P
In T = 30 years, Amount = 5P
∴ Interest received in 30 years = 5P - P = 4P
| Simple Interest = | PRT |
| 100 |
| ∴ 4P = | P x R x 30 |
| 100 |
4. When my father started working, he deposited some amount at simple interest in the bank. After 15 years the amount became 7 times. If the rate of interest remains, in how many more years will the amount become 10 times?
a. 3 years
b. 5 years
c. 7 years
d. 7.5 years
Answer: d. 7.5 years
Explanation:
Let initial amount = P
In T = 15 years, Amount becomes 7P
| So, Simple Interest = 7P - P = 6P = | P x R x 15 | ---------> As, SI = | PRT |
| 100 | 100 |
In how many years will amount become 10P?
R = 40%; Amount = 10P.
| So, Simple Interest = 10P - P = 9P = | P x 40 x T |
| 100 |
5. A certain amount becomes Rs 3000 at a simple interest of 12%. Keeping the time period same, if the rate of simple interest is increased by 3%, the amount will become 300 Rs/- more than in the previous setting. What is the amount? Also find the time period.
a. Rs. 1500 and 7 years
b. Rs. 1800 and 5.5 years
c. Rs. 1900 and 8.25 years
d. Rs. 2000 and 20 years
Answer: b. Rs. 1800 and 5.5 years
Explanation:
Let Simple Interest be S
Original sum 'P' and Time 'T' remains same
Also, 3% increase in rate of interested means, New rate = 15%
Increase of 300 Rs/- in the final amount means, New amount = Rs 3300/-
So, Amount 2 - Amount 1 = (P+S1) - (P+S2) = S1-S2
∴ 3300 - 3000 = S1-S2
∴ S1-S2 = 300
| ∴ | P x 15 x T | - | P x 12 x T | = 300 --------> As, Simple Interest = | PRT |
| 100 | 100 | 100 |
| ∴ | 3PT | = 300 |
| 100 |
For R = 15%,
| Simple Interest = | P x 15 x T | = | 10000 x 15 | = Rs. 1500 |
| 100 | 100 |
Also, PT = 10000
| ∴ T = | 10000 | = 5.55 years (Time period) |
| 1800 |


