| a. | 3 | Days |
| 5 |
| b. | 3 | Days |
| 4 |
| Answer: a. | 3 | Days |
| 5 |
| In 1 day 3 adults do | 1 | amount of work ; So, in 1 day, 1 adult does | 1/2 | = | 1 | work |
| 2 | 3 | 6 |
| In 1 day, 8 adults do | 1 | x 8 = | 4 | amount of work |
| 6 | 3 |
| In 1 day 4 boys do | 1 | amount of work; So, in 1 day, 1 boy does | 1/6 | = | 1 | work |
| 6 | 4 | 24 |
| In 1 day, 8 boys do | 1 | x 8 = | 1 | amount of work |
| 24 | 3 |
| In 1 day, 8 adults and 8 boys do | 4 | + | 1 | = | 5 | amount of work |
| 3 | 3 | 3 |
| ∴ 8 adults and 8 boys together complete the entire work in | 3 | days. |
| 5 |
| b. 6 | 2 | Days |
| 3 |
| c. 8 | 1 | Days |
| 5 |
| d. 10 | 2 | Days |
| 5 |
| Answer: b. 6 | 2 | Days |
| 3 |
Tip:
Understanding and solving such problems is very easy by drawing a line.

| In 1 day P does | 1 | work; And in 1 day Q does | 1 | work |
| 20 | 25 |
| In 10 days Q completes | 1 | x 10 = | 2 | work |
| 25 | 5 |
| Remaining work = 1 - | 2 | = | 3 | = Done by P and Q together |
| 5 | 5 |
| ∴ | 3 | = K x ( | 1 | + | 1 | ) |
| 5 | 20 | 25 |
| ∴ K = | 20 | = 6 | 2 | days = Days when P and Q worked together |
| 3 | 3 |
| Thus P leaves after 6 | 2 | days. |
| 3 |
Answer: a. 15 days
Explanation:
Let M and N together finish the work in 'X' days.
So, M when working alone takes 25 days more to complete the entire work.
And, N when working alone takes 1 week and 2 days (i.e.) 9 days more to complete the entire work.
Tip: In such cases, use the following trick -
X = Extra days of P x Extra days of Q
| b. | 60 | days |
| 11 |
| c. | 39 | days |
| 12 |
| d. | 15 | days |
| 8 |
| Answer: b. | 60 | days |
| 11 |
| In 1 hour, A completes | 1 | amount of work |
| 96 |
| In 1 hour, B completes | 1 | amount of work |
| 80 |
| Working together, in 1 hour A and B complete | 1 | + | 1 | = | 11 | amount of work |
| 96 | 80 | 480 |
| So they complete entire work in | 480 | hours. |
| 11 |
| Since they work for 8 hours per day, they need | 480 | x | 1 | = | 60 | days |
| 11 | 8 | 11 |
| a. | 24 | days |
| 7 |
| b. | 48 | days |
| 7 |
| d. 13 | 3 | days |
| 4 |
| Answer: d. 13 | 3 | days |
| 4 |
| In 1 day Ram does | 1 | amount of work |
| 16 |
| In 1 day Samar does | 1 | amount of work |
| 12 |
| So in 2 days, Work done = | 1 | + | 1 | = | 7 | amount of work |
| 16 | 12 | 48 |
| So in 12 days (i.e. 6 times 2days) work done = 6 x | 7 | = | 42 | = | 7 |
| 48 | 48 | 8 |
| Remaining work = | 1 |
| 8 |
| Now, on 13th day, Ram will work and complete | 1 | amount of work |
| 16 |
| Now, work remaining = | 1 | - | 1 | = | 1 |
| 8 | 16 | 16 |
| We know that in 1 day Samar will complete | 1 | amount of work |
| 12 |
| 1 | > | 1 |
| 12 | 16 |
| So, how long would Samar take to finish | 1 | of work? |
| 16 |
| = | 1 | ÷ | 1 | = | 3 |
| 16 | 12 | 4 |
| So answer is 13 + | 3 | days = 13 | 3 | days |
| 4 | 4 |