Answer: c. Rs. 800
Explanation:
| 1 day work of A = | 1 | ; 1 day work of B = | 1 |
| 12 | 16 |
| 1 day work of A+B+C = | 1 | = 1 day work of A + 1 day work of B + 1 day work of C |
| 6 |
| ∴ 1 day work of C = | 1 | - ( | 1 | + | 1 | ) = | 1 |
| 6 | 12 | 16 | 48 |
| Ratio of 1 day work of A, B and C = | 1 | : | 1 | : | 1 | = 4:3:1 ---------------- Multiplied by 48 |
| 12 | 16 | 48 |
| Share of C = | 1 | x Total Amount = | 1 | x 6400 = Rs. 800 |
| 4+3+1 | 8 |
Answer: b. Rs. 2500
Explanation:
| Total work of M = 1day work of M x 15 days = | 1 | x 15 = | 1 |
| 30 | 2 |
| Total work of N = | 1 | x 15 = | 1 |
| 45 | 3 |
| ∴ Total work done by M and N = | 1 | + | 1 | = | 5 |
| 2 | 3 | 6 |
| Remaining work = 1 - | 5 | = | 1 | = This is done by O |
| 6 | 6 |
| Share of O = Total work done by O x Total Amount = | 1 | x 15000 = Rs. 2500 |
| 6 |
Answer: a. Rs. 150
Explanation:
| Wages for 1 day for both = | Rs.2700 | = Rs. 900 |
| 3 |
| Daily wage of son = | 1 | x Wages for 1 day for both = | 1 | x 900 = Rs. 150 |
| 5+1 | 6 |
Answer: b. 55 Days
Explanation:
Let Prateek be absent for K days.
So, he worked for (100-K) days and got Rs. 840
He was fined for K days hence, his fine = Rs. 24 x K = 24K
∴ 840 = (100-K) x Rs. 48 - 24K
∴ 840 = 4800 - 48K - 24K
∴ K = 55 = Prateek was absent for these many days
Answer: c. Rs. 29
Explanation:
Since, Girls and Boys earn the same. Let us treat them to be all Boys.
So, 3 Girls + 3 Boys = 6 Boys
Let Daily wages of → Men=M; Women=W and Boys=B
6M=8W and 4W=6B -----------------> (1)
Also, 6M+4W+8B = Rs. 26
| ∴ 8W + 4W + 8 x | 4W | = Rs.26 ----------->Substituting values of M and B from 1 |
| 6 |
| ∴ M = | 8W | = Rs. 2 = Daily wages of 1 man |
| 6 |
| Also, B = | 4W | = Rs. 1 = Daily wages of 1 boy |
| 6 |